ACTIVITY ON OSCILLATION SYNTHESIS (ANALYTICAL SOLUTION) (2nd PROBLEM: SAME WIDTHS, DIFFERENT FREQUENCIES)
We are studying the synthesis of the two oscillations: x1(t) = A1 sin(w1 t), x2(t) = A2 sin(w2 t + f), f = 0, A1 = A2 = A.
The posistion of the body that performs the composite oscillation can be calculated as: x(t) = x1(t) + x2(t)
1) We can observe that analytically:
y(t) = x1(t) + x2(t) = A sin(w1 t) + A sin(w2 t) = A ( sin(w1 t) + sin(w2 t) ) = 2 A cos t sin t
If the two frequencies slightly differ, the factor A' = 2 A cos t changes in a slower pace than sin t that changes with frequency w' = .
That means that y(t) = A' sin (w' t), where w' = and A' = 2 A cos t .
2) We are calculating the values of y(t), t = 0 (0.2) T1+T2 and we are plotting the corresponding points (t, x(t)), t = 0 (0.2) T1+T2
t | 0 | 0.2 | 0.4 | 0.6 | 0.8 | 1. | 1.2 | 1.4 | 1.6 | 1.8 | 2. | 2.2 | 2.4 | 2.6 | 2.8 | 3. | 3.2 | 3.4 | 3.6 | 3.8 | 4. | 4.2 | 4.4 | 4.6 | 4.8 | 5. | 5.2 | 5.4 | 5.6 | 5.8 | 6. | 6.2 | 6.4 | 6.6 | 6.8 | 7. | 7.2 | 7.4 | 7.6 | 7.8 | 8. | 8.2 | 8.4 | 8.6 | 8.8 | 9. | 9.2 | 9.4 | 9.6 | 9.8 | 10. | 10.2 | 10.4 | 10.6 | 10.8 | 11. | 11.2 | 11.4 | 11.6 | 11.8 | 12. | 12.2 | 12.4 | 12.6 | 12.8 | 13. | 13.2 | 13.4 | 13.6 | 13.8 | 14. |
y(t) | 0. | 7.28692 | 14.3151 | 20.8355 | 26.6186 | 31.4626 | 35.2015 | 37.7106 | 38.9116 | 38.7749 | 37.3205 | 34.6167 | 30.7768 | 25.9549 | 20.3386 | 14.1421 | 7.59747 | 0.945077 | -5.57537 | -11.7342 | -17.3205 | -22.1498 | -26.0708 | -28.9702 | -30.7768 | -31.4626 | -31.0432 | -29.5758 | -27.1559 | -23.912 | -20. | -15.5955 | -10.8864 | -6.06443 | -1.31744 | 3.17837 | 7.26543 | 10.8106 | 13.7101 | 15.8924 | 17.3205 | 17.9916 | 17.936 | 17.2145 | 15.9139 | 14.1421 | 12.0221 | 9.6854 | 7.26543 | 4.89087 | 2.67949 | 0.732636 | -0.869308 | -2.07031 | -2.84079 | -3.17837 | -3.10719 | -2.6759 | -1.95439 | -1.02954 | -2.44929*10^^-15 | 1.02954 | 1.95439 | 2.6759 | 3.10719 | 3.17837 | 2.84079 | 2.07031 | 0.869308 | -0.732636 | -2.67949 |
Created by Mathematica (November 4, 2015) |